Can you solve the problem without a computer ??
No, only one point is shown, need to have a reference point to get a measurement. There are at least two possibilities... the point labeled zero and the horizontal center line.
No, only one point is shown, need to have a reference point to get a measurement. There are at least two possibilities... the point labeled zero and the horizontal center line.
Is it .500
This is solvable , no trick involved
Not saying its a trick, its only half a question. \"Location\" from what????? There IS more than one choice. I am guessing you are thinking the point marked \"zero\" but it could just as easy be the perpendicular distance from the centerline.
Or.. is it XY coordinates you are looking for?
Is it .500
No Sir
X .584 Y .7334 ?
No Sir
.500, .8125
No Sir
X .522 Y .778 ?
Calculated the angle and hypotenuse for the 1.00 x .375 triangle. With three sides known of the middle triangle, calculated the angle. Added the two angles and subtracted the result from 90. degrees and used the resulting angle to come up with X and Y.
Frank
Ohhhh that location.
bruski
Solution as Roller explained
34.209 degrees
bruski
34.209 degrees
bruski
How did you solve it ?
I can\'t draw it but it involved a few triangles from the tangents where the straight lines meet up with the diameters. I make for a terrible math teacher I know it.
bruski
Last One
Is it 38.577 degrees? I have been watching Joe Pieczynski channel which he is doing a series on rotary tables and there geometry right now.
bruski
Wow, you have the new book! Mine is dated 1962, LOL!
Frank
OK , last one again
Is it 20 degrees
bruski
Is it 20 degrees
bruski
No Sir,
The more that I stare at the triangles the more it looks like a pyramid in 3D.
bruski
When two lines intersect they make vertical angles
Anybody!!!!
Anybody!!!!
Ok 30 degrees
Anybody!!!!
29° 55\'. If that\'s not correct I will give up and wait for
the answer and solution. My brain can\'t take anymore.
Stirlingking
Ok 30 degrees
What allows you to rotate the purple line 50 deg? Why not 40, 55, or any random number. What geometric rule allows you to rotate it 50 degrees?
The angle labeled 50 degrees does not bear any relationship to the angle you make by rotating the line 50 deg that I I can see.
PS I did subtract the 50 deg from the 130 when I did it BUT later looking at it again decided that was not valid.
What allows you to rotate the purple line 50 deg? Why not 40, 55, or any random number. What geometric rule allows you to rotate it 50 degrees?
The angle labeled 50 degrees does not bear any relationship to the angle you make by rotating the line 50 deg that I I can see.
PS I did subtract the 50 deg from the 130 when I did it BUT later looking at it again decided that was not valid.
Do you agree the 50° has already been established as one angle of that triangle ?
If you agree, why think of a random number ? If not, what\'s your solution.
Do you agree the 50° has already been established as one angle of that triangle ?
If you agree, why think of a random number ? If not, what\'s your solution.
3 different triangles all meet at point F. ONE of them has a established 50 deg angle. (and its not the triangle with \"X\" that we are looking for) I\'m not sure which triangle your are referring to by \"that\" triangle.
I do not follow your explanation at all.
As I said, my solution was to subtract the 50deg from the 130 deg, thats how I came up with 30 degrees for a previous answer based on 180deg total for all angles in the triangle. However, when looking later, I could not see why I felt it was a valid operation at the earlier time. I still don\'t see any geometric rule that allows that.
3 different triangles all meet at point F. ONE of them has a established 50 deg angle. (and its not the triangle with \"X\" that we are looking for) I\'m not sure which triangle your are referring to by \"that\" triangle.
I do not follow your explanation at all.
As I said, my solution was to subtract the 50deg from the 130 deg, thats how I came up with 30 degrees for a previous answer based on 180deg total for all angles in the triangle. However, when looking later, I could not see why I felt it was a valid operation at the earlier time. I still don\'t see any geometric rule that allows that.
I concur. Rotating line segment AB 50° Clock Wise to make it fall on side EF (co-linear?)
This morning I notice something..... along with the purple line, there is also a purple arrow on the drawing. Rotating the line pointed to by the purple arrow 50 degrees WOULD be valid because that angle is defined.
Although Jerry\'s post said \"rotating the purple line\", perhaps he meant the purple arrow? I am guessing the purple arrow was put there for some reason.
I concur. Rotating line segment AB 50° Clock Wise to make it fall on side EF (co-linear?)
would require assuming angle AFE (vertex at F) was 50°, leaving me with no valid solution.Given triangle ABE was a 20° 20° 140° Isosceles triangle, ie having 2 equal sides,I assigned length values to the equal sides and solved for lengths of the legs of the trianglesto finally arrive at the last step. Since the little triangles were scalene and not right triangles,I had to do the a2 + b2 + 2 AB etc for each triangle which is why my brain is fried.My answer being 29° 55\' and not 30° is probably due to rounding errors. The slide rule I usedin basic electronics would have nailed it.I am anxiously waiting for more learning opportunities from the Forum.Stirlingking
3 different triangles all meet at point F. ONE of them has a established 50 deg angle. (and its not the triangle with \"X\" that we are looking for) I\'m not sure which triangle your are referring to by \"that\" triangle.
I do not follow your explanation at all.
As I said, my solution was to subtract the 50deg from the 130 deg, thats how I came up with 30 degrees for a previous answer based on 180deg total for all angles in the triangle. However, when looking later, I could not see why I felt it was a valid operation at the earlier time. I still don\'t see any geometric rule that allows that.
The corner of \"that\" triangle with 50 in the circle
Still many unanswered questions..... purple line, purple arrow, exactly which line is proposed to be rotated... etc etc
I am going back into watch mode.
What language are you guys speaking?
bruski
What language are you guys speaking?
bruski
Junior high math,1953I can’t speak for Stirlingking ☺☺
Stirlingking\'s responses are the sort of detail we were required to give in order to pass Geometry. We had to cite the specific axiom, theorem etc. that validated each operation as legal.
I completely concur with Stirlingking\'s post. I think a communications gap is what is leading to much of the confusion here, some of it has been rather cryptic.
I took and passed Geometry first in 1966 and later in college , its still very fresh in my memory.
Isn\'t Geometry the study of rocks? I\'m kidding, I meant rock formations.
bruski
Junior high math,1953I can’t speak for Stirlingking ☺☺
You’ve got got this Mr.B
Is that a petrified math equation from the Mesozoic era time period?
bruski
I’ve hit rock bottom on this thread, soI’ll try for more progress with the GG
Maybe that rock is from the Jurassic period. WMBOWS
Wash My Brain Out With Soap.
I would submit a witty post, but my fingers are talked out.
Stirlingking
\"This year will go down in history. For the first time, a civilized nation has full gun registration!
Our streets will be safer, our police more efficient, and the world will follow our lead into the future!\"
Adolph Hitler.....1934